A box of spherical candies is 23 g and its volume is 32.3 cm^3.

If the average mass of a single jawbreaker is 0.94g, what is the radius of a single jawbreaker?

**ANSWER:**

The radius of each jawbreaker is approximately** 0.68 cm.**

### Volume of a sphere;

**v = 4 /3 πr³**

where

r = radius

Therefore,

**23 g = 32.3 cm³**

0.94 g = ?

cross multiply

volume of a single jawbreaker = 32.3 × 0.94 / 23 = 30.362 / 23 = **1.32 cm³**

Therefore,

volume of each jawbreaker =** 4 /3 πr³**

**1.32 = 4 / 3 × 3.14 × r³**

r³ = 1.32 /4.18666666667

r³ = 0.31533683707

r = ∛0.31533683707

**r **= 0.680651651 = **0.68**

**Therefore, the radius of each jawbreaker is approximately 0.68 cm.**