## A strain gauge, having a gauge factor of 2, is mounted on a rectangular steel bar (Em =200×10° kN/m2), as shown in Figure.

A strain gauge, having a gauge factor of 2, is mounted on a rectangular steel bar (Em =200×10° kN/m2), as shown in Figure. The bar is 3 cm wide and 1 cm high, and is subjected to a tensile force of 30 kN. The voltage input vFlOV. 1)

Determine the resistance change of the strain gauge if the resistance of the gauge was 1200 in the absence of the axial load.

In the Wheatstone bridge circuit, all the resistors are 120 52, and it is balanced without external forces;

2) If the measurement device is able to measure 0 to 100 kN. It is required to have a resolution of 1 kN, please determine the gain needed for a 12-bit ±.5V sampling device;

3) Suppose the strain gauge is to be connected to a measurement device capable of determining a change in resistance with a stated uncertainty of 0.005 52 (95%). What uncertainty in stress would result when using this resistance measurement device?

## Suppose that Daniel has a 2.50 L bottle that contains a mixture of O2 , N2 , and CO2 under a total pressure of 5.20 atm.

Suppose that Daniel has a 2.50 L bottle that contains a mixture of O2 , N2 , and CO2 under a total pressure of 5.20 atm. He knows that the mixture contains 0.270 mol N2 and that the partial pressure of CO2 is 0.350 atm. If the temperature is 273 K, what is the partial pressure of O2

## A uniform electric field makes an angle of 60.0^{\circ}∘ with a flat surface.

A uniform electric field makes an angle of 60.0^{\circ} with a flat surface. The area of the surface is 6.66 \times 10^{-4} \mathrm{m}^{2}.

The resulting electric flux through the surface is 4.44 \mathrm{N} \cdot \mathrm{m}^{2} / \mathrm{C}.

Calculate the magnitude of the electric field.

## A copper rod with heat, capacity 585j.k is heated until it temperature change from 35°c to 80.

Question: A copper rod with heat, capacity 585j.k is heated until it temperature change from 35°c to 80.

Calculate the heat supply to the vod if the stt.c=390j/kg.k.

## A 0.250 L sample of seawater contains 77.4 g of NaCl which has a molecular weight of 58.44 ​g/mol.

A 0.250 L sample of seawater contains 77.4 g of NaCl which has a molecular weight of 58.44 ​g/mol.

What is the molar concentration of sodium chloride in the seawater?

## Hỗn hợp E gồm hai triglixerit X và Y có tỉ lệ mol tương ứng là 2 : 3.

Hỗn hợp E gồm hai triglixerit X và Y có tỉ lệ mol tương ứng là 2 : 3. Xà phòng hóa hoàn toàn E bằng dung dịch NaOH dư, thu được hỗn hợp muối gồm C15H31COONa, C17H31COONa và C17H33COONa. Khi cho m gam E tác dụng với H2 dư (xúc tác Ni, t°) thì số mol H2 phản ứng tối đa là 0,07 mol. Mặt khác, đốt cháy hoàn toàn m gam E, thu được 2,65 mol CO2 và 2,48 mol H2O. Khối lượng của X trong m gam E là

A. 24,96 gam.

B. 16,60 gam.

C. 17,12 gam.

D. 16,12 gam.

Quy đổi E thành (HCOO)3C3H5 (a), CH2 (b), H2 (-0,07)

nCO2 = 6a + b = 2,65

nH2O = 4a + b – 0,07 = 2,48

—> a = 0,05; b = 2,35

—> nX = 0,02 và nY = 0,03

Dễ thấy nH2 = 2nX + nY nên:

X là (C17H31COO)(C15H31COO)2C3H5

Y là (C17H33COO)(C15H31COO)2C3H5

—> mX = 16,60 gam

## A Period 2 element has the following successive ionization energies. Identify the element.

A Period 2 element has the following successive ionization energies. Identify the element.

1st: 1087 kJ/mol
2nd: 2353 kJ/mol
3rd: 4621 kJ/mol
4th: 6223 kJ/mol
5th: 37832 kJ/mol
6th: 47279 kJ/mol
7th: 55261 kJ/mol
8th: 69875 kJ/mol

## A box of spherical candies is 23 g and its volume is 32.3 cm^3.

A box of spherical candies is 23 g and its volume is 32.3 cm^3.

If the average mass of a single jawbreaker is 0.94g, what is the radius of a single jawbreaker?

The radius of each jawbreaker is approximately 0.68 cm.

### Volume of a sphere;

• v = 4 /3 πr³

where

Therefore,

23 g  = 32.3 cm³

0.94 g  = ?

cross multiply

volume of a single jawbreaker = 32.3 × 0.94 / 23 = 30.362 / 23 = 1.32 cm³

Therefore,

volume of each jawbreaker = 4 /3 πr³

1.32 = 4 / 3 × 3.14 × r³

r³ = 1.32 /4.18666666667

r³ = 0.31533683707

r = ∛0.31533683707

= 0.680651651 = 0.68

Therefore, the radius of each jawbreaker is approximately 0.68 cm.

## What is the density of aluminum chloride vapor (AlCl3) at 498 K and 0.939 atm?

(06.06 MC)

What is the density of aluminum chloride vapor (AlCl3) at 498 K and 0.939 atm?

a.  1.24 g/L
b.  3.06 g/L
c.  5.17 g/L
d.  7.42 g/L

## What is the volume of 0.80 grams of O2 gas at STP? (5 points) Group of choices 0.59 liters

What is the volume of 0.80 grams of O2 gas at STP? (5 points) Group of answer choices 0.59 liters 0.56 liters 0.50 liters 0.47 liters