If Chase needs to throw a basketball so that the path of the ball follows the curve of y=-x(x-3) at what point will the ball hit the ground?
Given y = -x(x-3) The ball will hit the ground when y = 0
-x(x-3) = 0 ==> x=0 or (x-3) = 0
x = 0
x-3 = 0 =>> x = 3
The ball will hit the ground at the point (3,0)